**August 2006**

In this issue:

- Two Processes
- Comparing the Variances
- Estimating the Variance
- Difference in Two Averages
- Example
- Summary
- Quick Links

Sometimes you will need to compare two processes. For example, you might be comparing the products from two different suppliers or from two sister plants. You might be comparing two ways of processing invoices. The question is, "Are the two processes making the same product?" This month's newsletter demonstrates how to compare the products from two different processes when there is no sufficient data to use control charts.

### Two Processes

How can the product from two processes differ? They can differ by the average value and by the amount of variation. For example, suppose you are comparing the purity of a product produced in Process A and in Process B. The calculated average purity from Process A will most likely be different from that calculated for Process B. Is this difference significant? Is there truly a difference in purity between the two processes? The calculated standard deviation (the variation) will also be different. Again, is this difference significant? In this newsletter, you will see how to compare the variances in two processes to see if they are the same. And if the variance is the same, you can construct a confidence interval for the difference in the two averages. This confidence interval will tell you if there is a significant difference in the two averages.

Suppose there are two processes (such as two different reactors) making the same product. Suppose n_{1} samples are taken from process 1 and n_{2} samples are taken from process 2. Some sample statistics can be calculated.

Process 1:

- Sample size: n
_{1} - Sample average: X
_{1} - Sample variance: s
_{1}^{2}

Process 2:

- Sample size: n
_{2} - Sample average: X
_{2} - Sample variance: s
_{2}^{2}

The procedure for comparing two processes is given below. This technique represents a snapshot in time for the two processes. You cannot be sure of obtaining similar results in the future unless the processes are in statistical control.

### Comparing the Variances

The approach used below to construct a confidence interval for the difference in two averages assumes that the variation is consistent between the two processes, i.e., each process has the same variance. This must be checked. To determine if two variances are the same, the F distribution is used.

To calculate the F value based on sample results, the larger sample variance is divided by the smaller sample variance.

F = Larger s^{2}/Smaller s^{2}

To determine if there is a difference in the variances of the two processes, this calculated value of F is compared to a critical F value from the tables for the F distribution. The table values of F depend on two degrees of freedom. v_{1} is the degrees of freedom in the variance in the numerator (n_{1} - 1). v_{2} is the degrees of freedom in the variance in the denominator (n_{2} - 1). The other item that the table values of F depend upon is the confidence coefficient (α). A value of α = 0.05 is typical.

Many statistical books contains the F tables. You can also determine the F value using Microsoft Excel's function FINV. This gives the critical value of F for a given confidence coefficient and the two degrees of freedom.

If the calculated value of F is larger than the table (critical) value, it is concluded that there is a difference in the two variances. If the calculated value is less than the table value, it is concluded that there are no differences in the two variances.

Once it has been determined that the variation is consistent between the two processes, the confidence interval for the difference between the two averages can be constructed.

### Estimating the Variance

The next step is to estimate the variance. If the variances are not the same between the two processes, you can not use this method. There are two estimates of the variance from the sample variances. These are pooled to get a single estimate of the variance. The pooled variance is given by the equation:

s_{p}^{2} = [(n_{1} - 1)s_{1}^{2} + (n_{2} - 1)s_{2}^{2}]/(n_{1} + n_{2} - 2)

The pooled variance is just a weighted average of the sample variances based on degrees of freedom for each sample. The square root of the pooled variance is a measure of the part-to-part variation or the process standard deviation using information from both samples.

### Difference in Two Averages

The pooled variance is used to help estimate the standard deviation, s_{diff}, which estimates the variation of differences in two sample averages.

s_{diff} =SQRT [s_{p}^{2}((1/n_{1})+ (1/n_{2}))]

This standard deviation is then used to construct a confidence interval around the difference in the two averages.

Let μ = present the true (unknown) average of a process. The 100(1 - α)% confidence interval for μ_{1} - μ_{2} is given by

X_{1} - X_{2} ± ts_{diff}

where t is the value for the t distribution corresponding to n_{1} + n_{2} - 2 degrees of freedom. The value of t can be found in the t tables of many statistics books. It is also available in Microsoft Excel using the TINV function.

If the confidence interval does not contain zero, it is concluded that the two processes are operating at different averages.

If the confidence interval does contain zero, you conclude that there is no evidence that the two processes are operating at different averages. They appear to have the same average.

### Example

In a plant, two different reactors are making the same product. The question was asked if the reactors produce the same yield. The data below were collected. Is there a difference in the yield from the two reactors?

The first step is to calculate the average and variance for each of the reactors. The variance is the square of the standard deviation. The results are:

Reactor 1:

- Average = 92.68
- Variance = 0.994
- Observations = 9

Reactor 2:

- Average = 92.18
- Variance = 0.480
- Observations = 8

The next step is to calculate the F value by dividing the larger variance (Reactor 1) by the smaller variance (Reactor 2).

F = Larger s^{2}/Smaller s^{2} = 0.994/0.480 = 2.07

The next step is to compare the calculated value of F with the critical value of F. There are 8 degrees of freedom in the numerator and 7 degrees of freedom in the denominator.

For α = 0.05, the critical value of F is 3.73 (using the FINV function in Excel). Since the calculated value of F is less than this, we conclude that the variance is consistent between the two reactors.

The pooled variance is then calculated.

s_{p}^{2} = [(9-1)0.994 + (8-1) 0.480]/(9 + 8 - 2) = 0.754

The next step is to calculate the s_{diff} =.

s_{diff} =SQRT[0.754((1/9)+(1/8))] = 0.422

The t value for α = 0.05 and 15 degrees of freedom is (using the TINV function in Excel):

t = 2.13

The 100 (1 - α)% confidence interval for μ_{1} - μ_{2} is given by

X_{1} - X_{2} ± ts_{diff}

92.68 - 92.18 ± 2.13(0.422)

0.5 ± 0.9

The 95% confidence interval for μ_{1} - μ_{2} is given by:

0.5 - 0.9 < μ_{1} - μ_{2} < 0.5 + 0.9

-0.4 < μ_{1} - μ_{2} < 1.4

Since the interval contains zero, we conclude that there is no evidence that the two reactors are operating at different yields.

Remember that this technique represents a snapshot in time of the processes. If the processes are not stable, you cannot be sure of getting a similar result in the future.

### Summary

This newsletter demonstrated how to compare two processes. The first step is to check if the variances of the two processes are the same by comparing the variances and using an F test to determine if they are the same. If they are, an estimate of the standard deviation is found from the combined data. The t distribution is used to put a confidence interval around the difference in means. If the confidence interval contains 0, we conclude that there is no difference in the means. If the confidence interval does not contain zero, we conclude that there is a difference in means.

### Quick Links

Thanks so much for reading our publication. We hope you find it informative and useful. Happy charting and may the data always support your position.

Sincerely,

Dr. Bill McNeese

BPI Consulting, LLC